Apps Calculator can't do decimals?

[Tarcin]

I am creating an Algebraic Calculator, and I am running into some problems. I use Eclipse, and someone complained that they couldn't use negative numbers. So I fixed that, but while testing, I noticed that whenever I tried to input a decimal for A, B, or C the application would crash. Can anyone help me? If you guys really need it I wouldn't mind pming my code.

Thanks!
Tarcin

 

[BobPaul]

I'd like to help out but it's gonna be hard to with such little info given. What do you mean by "A, B or C"?

 

[pietjuhhh1990]

Ar you using an Int value for the number (those can't do decimals)
With double you can have 2 digets behinde the ,)
float is fully open

 

[Tarcin]

by A, B, and C I mean Ax^2+Bx+C

@piet: yeah I'm using int... do I just replace int for float?

 

[Tarcin]

String a = (String)et1.getText().toString();
String b = (String)et2.getText().toString();
String c = (String)et3.getText().toString();
String d = (String)et4.getText().toString();
Int inta = Integer.parseint(a);
Int intb = Integer.parseint(b);;
Int intc = Integer.parseint(c);
Int intd = Integer.parseint(d);
float f1 =(float)((floatb-floata)/(floatd-floatc));
String sx = "Slope= " + f1;
tv6.setText(sx);

 

[pietjuhhh1990]

for the calculator us a tryparse for the nubers if you'll input a character like "e" the app will crash

 

[Tarcin]

So if I replace it with Float what should I put on the parse part?

Float floatd = Float.parse??(d);

 

[JamTheMan]

Yeah... Just use floats instead:

Float floatA = Float.parseFloat(a);

 

[Tarcin]

I fixed it by using floats, thanks!

 

[id0001]

Ar you using an Int value for the number (those can't do decimals)
With double you can have 2 digets behinde the ,)
float is fully open

Actually doubles can have a lot more decimals. Also doubles are more precise than floats since doubles use 64 bit and floats use only 32 bits.