Sanforalini
Lurker
(from http://source.android.com/tech/security/index.html):
(complete sentence; couldn't get it entirely in the title):
<quote>
Like all security features, the Application Sandbox is not unbreakable. However, to break out of the Application Sandbox in a properly configured device, one must compromise the security of the the Linux kernel.
</quote>
Whilst this sounds like quite the bold statement, it might cause the slightest grin on the face of many sysadmins.
Although I surely couldn't break the Linux kernel, compared to BSD flavors of Unix, it's not looked upon as the most secure OS.
Hence also the existence of the security enhanced Linux kernel.
(If the kernel is hyper-secure, why need a security enhanced version?)
So, without further ado, my question
:
Does android uses the security enhanced Linux kernel?
If so, why is this not explicitly mentioned on their site:
Android Security Overview | Android Open Source
?
If not,
why not?
best regards,
S.
ps: I'm kinda glad I can include links after my, albeit slightly vexed, introduction :$
(complete sentence; couldn't get it entirely in the title):
<quote>
Like all security features, the Application Sandbox is not unbreakable. However, to break out of the Application Sandbox in a properly configured device, one must compromise the security of the the Linux kernel.
</quote>
Whilst this sounds like quite the bold statement, it might cause the slightest grin on the face of many sysadmins.
Although I surely couldn't break the Linux kernel, compared to BSD flavors of Unix, it's not looked upon as the most secure OS.
Hence also the existence of the security enhanced Linux kernel.
(If the kernel is hyper-secure, why need a security enhanced version?)
So, without further ado, my question
:Does android uses the security enhanced Linux kernel?
If so, why is this not explicitly mentioned on their site:
Android Security Overview | Android Open Source
?
If not,
why not?
best regards,
S.
ps: I'm kinda glad I can include links after my, albeit slightly vexed, introduction :$