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Riddle me this!

Well it's been all of 5 minutes and there's no new riddle so I'll add another :p

Your outside a room, that contains 4 lightbulbs. Outside the room is 4 switches one for each lightbulb.
The door to the room is closed and you can't see inside.

You have to figure out which lightbulb connects to which switch while only going inside once.

(and no you can't pop your head in through the door while pressing the switches with your hand)
 
Ozymandias88 said:
Well it's been all of 5 minutes and there's no new riddle so I'll add another :p

Your outside a room, that contains 4 lightbulbs. Outside the room is 4 switches one for each lightbulb.
The door to the room is closed and you can't see inside.

You have to figure out which lightbulb connects to which switch while only going inside once.

(and no you can't pop your head in through the door while pressing the switches with your hand)
Click to expand...
I'd put a mirror under the door crack and see what lightbulbs light up or if the room has a window, i'll run to it and check everytime I switch the switch
 
Ozymandias88 said:
Well it's been all of 5 minutes and there's no new riddle so I'll add another :p

Your outside a room, that contains 4 lightbulbs. Outside the room is 4 switches one for each lightbulb.
The door to the room is closed and you can't see inside.

You have to figure out which lightbulb connects to which switch while only going inside once.

(and no you can't pop your head in through the door while pressing the switches with your hand)
Click to expand...

I know the answer if it's three light bulbs. Assuming you can't cheat by seeing in the room some other way, I'm not sure it's possible with four. In case I'm heading in the right direction:

Are these traditional light bulbs (read as: do they get hot when you turn them on?)
 
akazabam said:
I know the answer if it's three light bulbs. Assuming you can't cheat by seeing in the room some other way, I'm not sure it's possible with four. In case I'm heading in the right direction:

Are these traditional light bulbs (read as: do they get hot when you turn them on?)
Click to expand...

That's right, I'm going to quote myself.

Following my previous question, I guess this is potentially possible with four:

Turn on switches 1 and 2, and wait a few minutes. Turn off switch 2 and turn on switch 3, then quickly go in the room. The light that is on and feels hot goes with switch 1; the light that is off, but hot goes with switch 2; the light that is on, but not as hot goes with switch 3; and the light that is off and cool goes with switch 4. Am I right?
 
akazabam said:
That's right, I'm going to quote myself.

Following my previous question, I guess this is potentially possible with four:

Turn on switches 1 and 2, and wait a few minutes. Turn off switch 2 and turn on switch 3, then quickly go in the room. The light that is on and feels hot goes with switch 1; the light that is off, but hot goes with switch 2; the light that is on, but not as hot goes with switch 3; and the light that is off and cool goes with switch 4. Am I right?
Click to expand...

Correct! I think I'm out of riddles now though so someone else is going to have to think of one. I'm looking at you akazabam being you got the last one right.
 
A mother is 21 years older than her son.
In 6 years time the son will be 5 times younger than the mother.
Where is the father?
 
akazabam said:
A mother is 21 years older than her son.
In 6 years time the son will be 5 times younger than the mother.
Where is the father?
Click to expand...

What I have come up with so far.

Mother is 24 when she has the kid. 6 years later she is 30 and 30 is 5 times 6 so the kid would be 6. Not sure about the father thing yet.

Let me know if I am on track or if this even matters.
 
CT53 said:
What I have come up with so far.

Mother is 24 when she has the kid. 6 years later she is 30 and 30 is 5 times 6 so the kid would be 6. Not sure about the father thing yet.

Let me know if I am on track or if this even matters.
Click to expand...

The math fits, but I'm sure it fits with other numbers, and that doesn't help you with the question.

gallandof said:
there is no father, its an adopted child?
Click to expand...

Nope.


Small hint:
algebra
 
numbers don't add up. If the child is -9 now, then in 9 months the girl could be 21 or 22. Add 6 to either and you get 27 or 28. In 6 years, the boy will be 5 years and 3 months, which times 5 is 25 +15 months, which is 26 and 3 months old, still not quite enough considering the girl has to be 27 minimum.

Sorry, math major here.... :p
 
johnlgalt said:
numbers don't add up. If the child is -9 now, then in 9 months the girl could be 21 or 22. Add 6 to either and you get 27 or 28. In 6 years, the boy will be 5 years and 3 months, which times 5 is 25 +15 months, which is 26 and 3 months old, still not quite enough considering the girl has to be 27 minimum.

Sorry, math major here.... :p
Click to expand...

well its nine months so its, -3/4 years.

If x is the current age of the kid and y is current age of the mother, then x+21 = y.
six years from now, the mom will be 5 times as old as her kid, so:
5(x+6) = y+6.
Now substituting:
5x + 30 = x+21+6
4x = -3
x = -3/4, which is 9 months.

well according to your theory, the current age of the mom should be 20 years and 3 months. Add 6 years, you get 26 years and 3 months. multiply 5 years and 3 months by 5 and you get 26 years and 3 months, which is the answer. You chose the wrong 'mothers age' to multiply to, hope you get it :P
 
johnlgalt said:
numbers don't add up. If the child is -9 now, then in 9 months the girl could be 21 or 22. Add 6 to either and you get 27 or 28. In 6 years, the boy will be 5 years and 3 months, which times 5 is 25 +15 months, which is 26 and 3 months old, still not quite enough considering the girl has to be 27 minimum.

Sorry, math major here.... :p
Click to expand...

scarecrow95 said:
well its nine months so its, -3/4 years.

If x is the current age of the kid and y is current age of the mother, then x+21 = y.
six years from now, the mom will be 5 times as old as her kid, so:
5(x+6) = y+6.
Now substituting:
5x + 30 = x+21+6
4x = -3
x = -3/4, which is 9 months.

well according to your theory, the current age of the mom should be 20 years and 3 months. Add 6 years, you get 26 years and 3 months. multiply 5 years and 3 months by 5 and you get 26 years and 3 months, which is the answer. You chose the wrong 'mothers age' to multiply to, hope you get it :P
Click to expand...

...man that was confusing >_>;;;
 
In terms of -3/4 it makes much more sense, b/c then the mother is not 21 yet, which as you pointed out was the flaw in my calculations.

Thanks for making me see the forest that was being blocked by all the trees. :p
 
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